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A rocket is launched from the origin with an acceleration of 20m/s^2 at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80m/s^2 downward.

-Ignoring air resistance.

What is the maximum velocity in the upward direction?

I used: final velocity = initial velocity + acceleration * time

Which putting in the values I got: Vf = 0 + (20(sin30))(2) = 20m/s

I also have another way

Vf = 20(sin30) + (9.8)(2) = 29.6m/s

I don't know which one is right if either

Here are the answers selections: (a) 20.0 (b) 25.0 (c) 30.0 (d) 35.0 (e) 40.0

He might or might have not rounded them.

The next question I can't even begin

What is the maximum height?

I use the equation y = Vi + 1/2at^2 and I don't get the correct answer

Here are the answers selections: (a) 22.3 (b) 27.5 (c) 30.5 (d) 36.7 (e) 40.4

I’m so frustrated I want to bit my head off especially since its multiple choices.

Please in need of Help.