Ok I've been trying to do a problem and I can't seem to get it. A rocket is launched from the origin with an acceleration of 20m/s^2 at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80m/s^2 downward. -Ignoring air resistance. What is the maximum velocity in the upward direction? I used: final velocity = initial velocity + acceleration * time Which putting in the values I got: Vf = 0 + (20(sin30))(2) = 20m/s I also have another way Vf = 20(sin30) + (9.8)(2) = 29.6m/s I don't know which one is right if either Here are the answers selections: (a) 20.0 (b) 25.0 (c) 30.0 (d) 35.0 (e) 40.0 He might or might have not rounded them. The next question I can't even begin What is the maximum height? I use the equation y = Vi + 1/2at^2 and I don't get the correct answer Here are the answers selections: (a) 22.3 (b) 27.5 (c) 30.5 (d) 36.7 (e) 40.4 I’m so frustrated I want to bit my head off especially since its multiple choices. Please in need of Help.