Need help on Motion in a Resistive Medium

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The motion of a body in a resistive medium is described by the equation dv/dt = Bv - Av^2, where B and A are constants. To find the initial acceleration, set v to 0, resulting in a = 0. For the velocity at which acceleration becomes zero, the equation is set to zero: 0 = Bv - Av^2. This leads to the conclusion that acceleration ceases when Bv equals Av^2. Understanding these calculations is crucial for analyzing motion in resistive environments.
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1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2.


2. Find it's initial acceleration.
Find the velocity at which the acceleration becomes zero.


3. B and A are constants.

dv/dt = acceleration = Bv - Av^2.

vf = vi + at
vf = 0 + Bv - Av^2(t)
vf = Bv - Av^2(t)

Where am I going with this?
 
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dv/dt is acceleration.

a. So, when it says find the initial acceleration you just set v=0.
a= B(0) - A(0)2


b. To find the velocity at which accleration becomes 0, you set the whole equation to 0.
0=Bv - Av2
 
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