An object is launched from earth as a projectile. At the top of its trajectory the object breaks into separate pieces at a horizontal distance 300m from the launch point. One piece has 1/4 of the mass of the initial object and the other piece has 3/4 of the mass of the initial object. The smaller piece falls straight to the ground while the larger continues its motion.
At what horizontal distance from the launch point does the larger piece land?
Do I need to use a projectile motion equation?
M1 = 1/4m
M2 = 3/4m
Vy = 0 m/s
The Attempt at a Solution
I know that both pieces will hit the ground at the same time b/c of 1-D kinematics.
I'm so lost but here's an attempt:
For 1/4m = M1
(M1)gh = 1/2mv^2
(1/4m)gh = 1/2(1/4m)v^2
Okay now I don't have height or anything??