Need help understanding this circuit.

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The discussion centers on understanding a finger plethysmograph circuit, specifically the role of a 10K potentiometer labeled as gain. It controls the fraction of the output signal from the first op-amp that feeds into the second, providing variable attenuation and thus influencing the overall gain. Participants analyze the circuit's filtering components, identifying a high-pass filter formed by a 10µF capacitor and a 20KΩ resistor, while a combination of a 100KΩ resistor and a 0.47µF capacitor serves as a low-pass filter, creating a band-pass filter effect. The circuit is confirmed to measure pulse rate by utilizing infrared light and a phototransistor. Overall, the circuit's design effectively filters and amplifies signals for pulse detection.
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This is finger plethysmograph i found on Cornell site. I can kind of understand how the circuit works, but i am confused on the circuitry around the op amps, especially the 10K potentiometer, i have no idea what that does.
My guess is 10uf cap and 20K ohm is a high pass filter and a low pass filter (the 100K ohm and .47uf cap) is fed back to the inverting input for amplification. Please correct me if i am wrong.
Any help is greatly appreciated.:smile:
 
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Welcome to PF integrant2.

Did you notice that the 10 kΩ pot is labeled gain?
 
dlgoff said:
Welcome to PF integrant2.

Did you notice that the 10 kΩ pot is labeled gain?
Yes i did. Does that mean that pot controls the gain on the op amp in the middle or both?
 
integrant2 said:
Yes i did. Does that mean that pot controls the gain on the op amp in the middle or both?
Specifically it controls what fraction of the signal from the output of the first op-amp makes it to the input of the second op-amp circuit. It provides a variable attenuation which ultimately of course controls the gain of the overall circuit.
 
Thanks a lot for the reply, it helps me a lot.
But how about my guess on the filters? I am quite sure the 10uf and 20KOhm is a high pass filter, but how about the 100KOhm and 0.47uf in parallel? Is that a low pass filter?
 
The 10uf and 20KOhm looks like it would be a very low frequency (0.1 Hz) filter and the 100KOhm and 0.47uf would pass around 21 Hz.
 
integrant2 said:
Thanks a lot for the reply, it helps me a lot.
But how about my guess on the filters? I am quite sure the 10uf and 20KOhm is a high pass filter, but how about the 100KOhm and 0.47uf in parallel? Is that a low pass filter?

It's a crude way to do it, but the combination of a low pass filter and a high pass filter provides a simple band pass filter. In this case the high pass filter cuts in about 0.8Hz and the low pass cuts off at about 3.4 Hz. The fact that two of these stages are cascaded however reduces the pass band somewhat.

BTW Integrant2. Is this for measuring pulse rate? The frequencies look about right for that purpose.
 
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uart said:
It's a crude way to do it, but the combination of a low pass filter and a high pass filter provides a simple band pass filter. In this case the high pass filter cuts in about 0.8Hz and the low pass cuts off at about 3.4 Hz. The fact that two of these stages are cascaded however reduces the pass band somewhat.

BTW Integrant2. Is this for measuring pulse rate? The frequencies look about right for that purpose.

Yea, it measures the pulse rate by shining IR into the finger tip, then the phototransistor on the other side detects the signal and transmit it to the op amps for filtering and amplification.


But anyway, thank you so much for the help, you guys are really helpful :)
 
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