Need help with a simple integral involving u substitution

  • Thread starter Thread starter XtremePhysX
  • Start date Start date
  • Tags Tags
    Integral
XtremePhysX
Messages
92
Reaction score
0

Homework Statement



Find:

Homework Equations



\int \sqrt{\frac{x}{1-x}}dx

The Attempt at a Solution



I tried to use u substitution with u=1-x but it did work.
 
Physics news on Phys.org
bump :)im really sorry, I am new here. Please excuse my actions.
where can i find the rules to read them?
 
Last edited:
XtremePhysX said:

Homework Statement



Find:

Homework Equations



\int \sqrt{\frac{x}{1-x}}dx

The Attempt at a Solution



I tried to use u substitution with u=1-x but it did work.

XtremePhysX said:
bump :)

The moderators will likely slap your wrist for bumping within an hour of posting if they see it. I might try something like ##x=\sin^2\theta## and see what happens.
 
Hi XtremePhysX! :smile:

Try integrating by parts, or a trig substitution. :wink:
 
I found it =)

I used x=sin^2theta

and the answer is sin^{-1}\sqrt{x}-\frac{sin2(sin^{-1}\sqrt{x})}{2}how do i simplify it now?
 
instead of using sin2θ, write it as 2sinθcosθ :smile:

(but when you've done all that, start again and try it with integration by parts :wink:)
 
sin^{-1}\sqrt{x}-\frac{2sin(sin^{-1}\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(\sqrt{1-x})}{2}

Is this right?
 
XtremePhysX said:
sin^{-1}\sqrt{x}-\frac{2sin(sin^{-1}\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(\sqrt{1-x})}{2}

Is this right?

No. Call ##\theta = \arcsin({\sqrt x})##. You have ##\theta - \sin\theta \cos\theta## which is equal to ##\theta - \sqrt x \sqrt{1-\sin^2\theta}=\arcsin\sqrt x-\sqrt x \sqrt{1-x}##, which you can verify is correct by differentiating it.
 
(just got up :zzz:)

in other words cos(sin-1√x) = √(1 - x)

(because if y = sin-1√x, then √x = siny so x = sin2y so 1 - x = cos2y, so cosy = √(1 - x) :wink:)
 
  • #10
XtremePhysX said:
bump :)


im really sorry, I am new here. Please excuse my actions.
where can i find the rules to read them?

I see you edited your post after the premature bump. Yes, please do not bump your post after just an hour -- the PF rules specify that you must wait at least 24 hours before making a single bump post.

EDIT -- And the Rules link is at the top of every PF page.
 

Similar threads

Replies
96
Views
4K
Replies
12
Views
2K
Replies
22
Views
3K
Replies
8
Views
2K
Replies
44
Views
5K
Replies
3
Views
2K
Replies
15
Views
2K
Replies
5
Views
1K
Back
Top