Need help with assignment force question

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    Assignment Force
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To calculate the electrostatic force between two electrons separated by one meter, the formula F = (q1 * q2) / (4 * π * ε0 * d^2) is used, where q1 and q2 are the charges of the electrons, ε0 is the permittivity of free space, and d is the distance between the charges. Given that the charge of an electron is -1.6 x 10^-19 C, the calculation involves substituting these values into the formula. The constant κ, which is approximately 8.9876 x 10^9 N m^2/C^2, simplifies the calculation. The final answer for the force is a negative value, indicating an attractive force between the electrons. Understanding these principles is crucial for solving problems related to electrostatics.
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I am stumped on this question. Can anyone advise?

The electric charge of an electron is -1.6 X 10 to the -19 power C.
What is the force exerted between two electrons separated by one meter?
 
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The electrostatic force between two charged particles is
F=\frac{q_1.q_2}{4\pi\epsilon_0.d^2}
where \epsilon_0 is the permitivity of free space and
\kappa = \frac{1}{4\pi\epsilon_0} = 8.9876.10^9 N m^2 C^{-2}
 
My answer is

<< solution removed by berkeman >>
 
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