Need help with electricity

  • Thread starter Noiro
  • Start date
1. The problem statement, all variables and given/known data

100[tex]\Omega[/tex] resistance wire is cut in equal parts, which are combined in parallel. They're total resistance is 1[tex]\Omega[/tex]. In how many parts the wire is cut?

2. Relevant equations

I guess it's something like [tex]R[/tex]=[tex]\frac{R_{1}}{N}[/tex]

3. The attempt at a solution
I don't have an idea how to solve it :frown: I would be very grateful if someone could help me solve this problem.
Think of the resistance wire as many small resistors connected together. Because the resistors are connected together in a series, the total resistanse in the "first" situation will be

nR=100 (1)

Here "n" is the number of resistors (number of resistanse wire parts) and R is the resistanse of a part of resistanse wire. Since the pieces are cut in identical pieces they will also have the same "independent" resistanse.

Further we know that if we combine the parts in parallel we get the resistanse as


Because R.1=R.2=R.3... (and so forth) we get



R.tot=R=n (2)

Again, R.1=R.2=R.3 because the pieces are identical

Solving for (1) and (2) gives that we have 10 pieces.
Sorry for my hasty reply, the second eqation should be


otherwise it's fine
Thank you very much, Ofey!

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