Need Help with HS Physics Problem? Calculate Total Distance Traveled

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To solve the physics problem, the object first travels at a velocity of 10 m/s for 3 seconds, covering a distance of 30 meters. Then, it moves at 5 m/s for 2 seconds, adding another 10 meters. The total distance traveled is the sum of these two distances, resulting in 40 meters. The discussion emphasizes the importance of using the formula d = vt for calculating distance. Clarifications about distance versus displacement and the relevance of speed-time graphs are also mentioned.
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Can u help me solve this HS Physics problem?

Any help will be appreciated! :smile:

1.) An object travels in a straight line at a uniform velocity of 10 m/s for 3 seconds and then travels for 2 seconds at constant speed of 5 meters per second in the same direction. Calculate the total distance traveled.
 
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If I move at 10 m/s, that means I move a distance of 10 metres every second. So if I travel at that velocity for 3 whole seconds, how far have I gone? Do you see that d = vt is all you need for this problem. More importantly, do you see why it applies from my description?
 
lol becareful distance and displacement displacement is a vector
 
He does mention its in the same direction. If you have graph of the above data, then the area under the graph equals distance travelled(speed-time graph)
 
so i haev 2 answers one 50 mph and one 65 mph , they probley are both wrong, but i used two different equations and obtained two different answers!?
 
SpeedeRi2 said:
An object travels in a straight line at a uniform velocity of 10 m/s for 3 seconds
So how far does it travel in those first 3 seconds?
and then travels for 2 seconds at constant speed of 5 meters per second in the same direction.
And how far does it travel in these 2 seconds?

So... what's the total distance traveled?
 
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