Dec 7, 2007 #1 michaeljlyons Messages 3 Reaction score 0 Homework Statement calculate Δƒ/Δx and Δƒ/Δy. ƒ(x,y) = x(y^2) + (x^2)y any help will be appreciated
Dec 7, 2007 #2 cristo Staff Emeritus Science Advisor Messages 8,144 Reaction score 75 You need to show some work before we can help you. In order to attempt the question, you first need to know what Δƒ/Δx and Δƒ/Δy are. Can you tell us?
You need to show some work before we can help you. In order to attempt the question, you first need to know what Δƒ/Δx and Δƒ/Δy are. Can you tell us?
Dec 7, 2007 #3 michaeljlyons Messages 3 Reaction score 0 well what i did was Δƒ/Δx = 2*x*y + y^2 Δƒ/Δy = x^2 + 2*x*y but iam not sure if iam doing this right f(x,y) confuses me forgot how to deal with this Last edited: Dec 7, 2007
well what i did was Δƒ/Δx = 2*x*y + y^2 Δƒ/Δy = x^2 + 2*x*y but iam not sure if iam doing this right f(x,y) confuses me forgot how to deal with this
Dec 7, 2007 #4 Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 It looks like you are taking partial derivatives of f(x,y) wrt to x and y. IF that's what you were trying to do, then you are in good shape.
It looks like you are taking partial derivatives of f(x,y) wrt to x and y. IF that's what you were trying to do, then you are in good shape.
Dec 7, 2007 #5 michaeljlyons Messages 3 Reaction score 0 so then my answer Δƒ/Δx = 2*x*y + y^2 Δƒ/Δy = x^2 + 2*x*y is correct right? for f(x,y)
Dec 7, 2007 #6 Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 Whether your answer is correct depends on what the question is. It's right if your delta notation is supposed to mean 'partial derivative'. It's not the usual notation.
Whether your answer is correct depends on what the question is. It's right if your delta notation is supposed to mean 'partial derivative'. It's not the usual notation.