Need help with Newtons third law and friction.

AI Thread Summary
The discussion revolves around solving a physics homework problem related to Newton's third law and friction. The user initially struggles with setting up free body diagrams (FBDs) and equations for the forces acting on two objects, Garfield and a mug. Key points include the importance of applying Newton's second law in both x and y directions and recognizing that the net force on the mug is zero since it is not accelerating. Additionally, the tension in the ropes must be resolved into components to accurately analyze the forces. The user expresses progress in understanding the concepts but seeks clarification on handling multiple tensions in a subsequent question.
cruisx
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Homework Statement



Hi guys i am trying to do question number 4 but i have not done a Question liek this in a very long time so i am forgetting where to start.

http://img405.imageshack.us/img405/6976/101420092845.jpg"

Image is to big for the forum so its easier that way.

Homework Equations


The Attempt at a Solution



Ok so first thing i did was make some FBDs and got my equations, idk if this is the first thing i should do...

for Garfield

Fnet = T+Fg
ma = mg-T

and for the mug

Fnet = T (since FN and FG cancel out correct)

Like i said its been about a year so i am rusty, could someone help me get the correct answer for 4?

thanks.
 
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cruisx said:
Fnet = T+Fg
ma = mg-T

Unless you mean for Fnet, T, and Fg to be vectors, you have to write down Newton's second law for both the x and y directions. (You can't add forces unless they're acting in the same direction or opposite directions.) Keep in mind that the force pulling Garfield up is not T; it's the horizontal component of T.
and for the mug

Fnet = T (since FN and FG cancel out correct)

Actually, Fnet has to be 0 because the mug isn't acceleration. Again, write Newton's second law in both the x and y directions, and note that the tension in the diagonal rope isn't the same as the tension in the horizontal rope.
 
Resolve tension in the rope attached to the wall into components. At equilibrium, vertical component balances the weight of Garfield, horizontal component balances the friction force between mug and the table. Mass of the mug is given. Assume m as the mass of the coffee. from that find the total normal reaction and hence frictional force.
 
Ok thansk guys, i understand it better now, i am am makign progress. I don't want to make another topic so i will just ask here.

In Question number 2a, I would start by making an FBD then an equation for each mass correct? and then using those equations to find T1 and T2? But i am confused because they are two different tensions and my examples have not dealt with a Question like this.
 
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