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Need help with this Integral

  1. May 12, 2005 #1
    Hey whats up..I need a little help with the following problem.

    If [tex]\int_{-\frac{\pi}{2}}^{M} \cos x dx= 1.5}[/tex], find M.

    How do I go about doing this? I know that...the anti derivative of cos is sin, and that [tex] \sin x \right]_{-\frac{pi}{2}}^{M} = 1.5[/tex]

    Any help would be greatly appreciated...
     
  2. jcsd
  3. May 12, 2005 #2

    James R

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    [tex]\sin x |^M_{-\pi/2} = \sin M - (-\pi/2) = 1.5[/tex]

    Are you ok from there?
     
  4. May 12, 2005 #3
    ahhh..DUH! goshh...how did i NOT see that??? Thanks man...haha...
     
  5. May 13, 2005 #4

    dextercioby

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    It was a typo/error in post #2.

    [tex] \sin x\left |_{-\frac{\pi}{2}}^{M}\right =1.5\Rightarrow \sin M+\sin\frac{\pi}{2}=1.5\Rightarrow \sin M +1 =1.5[/tex]

    Daniel.
     
  6. May 14, 2005 #5

    James R

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    Oops! You're right, of course.
     
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