Need help with this Integral

  • Thread starter ziddy83
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  • #1
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Hey whats up..I need a little help with the following problem.

If [tex]\int_{-\frac{\pi}{2}}^{M} \cos x dx= 1.5}[/tex], find M.

How do I go about doing this? I know that...the anti derivative of cos is sin, and that [tex] \sin x \right]_{-\frac{pi}{2}}^{M} = 1.5[/tex]

Any help would be greatly appreciated...
 

Answers and Replies

  • #2
James R
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[tex]\sin x |^M_{-\pi/2} = \sin M - (-\pi/2) = 1.5[/tex]

Are you ok from there?
 
  • #3
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ahhh..DUH! goshh...how did i NOT see that??? Thanks man...haha...
 
  • #4
dextercioby
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It was a typo/error in post #2.

[tex] \sin x\left |_{-\frac{\pi}{2}}^{M}\right =1.5\Rightarrow \sin M+\sin\frac{\pi}{2}=1.5\Rightarrow \sin M +1 =1.5[/tex]

Daniel.
 
  • #5
James R
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Oops! You're right, of course.
 

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