Need to make sure I am doing these problems correctly.

  • Thread starter Thread starter Jdpaul88
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Jdpaul88
Messages
8
Reaction score
0
Measurement problems: Mass, weight, unit conversion

Homework Statement


There are 8 pints to a gallon. One gallon of good English Bitter, ready to drink, has a mass of 3.831 Kg. One gallon of pure clear water, also at drinking temperature, has a mass of 3.785 Kg. A pound, on the other hand, is anything that has a mass of 0.4535 Kg. There are, by definition, 16 ounces in a pound

a. How heavy is a pint of English Bitter in pounds
b. How heavy is a pint of pure clear water in pounds
c. How much more massive is a pint of Bitter than a pint of water in ounces?


Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces



The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?
 
Last edited:
on Phys.org


Jdpaul88 said:

Homework Statement



Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces

The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?

Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.
 


LowlyPion said:
Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.

Thanks for the input. Good to meet you.
 
So you think that this setup is fine?