Is Cu(ClO4)2 Omitted in Net Ionic Equations?

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Cu(ClO4)2 is soluble and should be omitted from the net ionic equation, leaving only H2O. The discussion highlights that soluble compounds do not appear in net ionic equations, while insoluble compounds like Cu(OH)2 must be included. The distinction is crucial for accurately representing the chemical reaction. The presence of (s) indicates a solid, emphasizing its importance in the equation. Understanding solubility rules is essential for correctly writing net ionic equations.
ChrisEffinSmi
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I've been struggling with this for a while now. Cu(ClO4)2 is soluble so it should drop from both sides of the net ionic equation, right? Leaving only H20. Am I missing something?

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Cu(OH)2 is insoluble. There is a reason why it is marked with (s).

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methods
 
But if you have something solid like Cu(OH)2, you need to leave it in the equation, regardless of whether any of its ions (such as Cu2+) have separated on the other side of the equation.
 

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