1. The problem statement, all variables and given/known data So I've calculated the person's corrective lens to need the power of -2.00D now I must find the new near point with the corrective lens on. The initial near point is 15cm and I converted the -2.00D in to cm, which is -50cm (I hope). 2. Relevant equations I've used this formula - 1/f = 1/v + 1/u v = image distance u = object distance 3. The attempt at a solution My attempt so far looks like this... I have an answer but need someone more experienced to tell me if it seems right: 1/f = 1/0.019m + 1/-0.35m = 49.7m So would the new near point be 49.7m? Any help would be really appreciated, thanks!