Newtonian Mechanics - single particle

McHead36
Messages
3
Reaction score
0

Homework Statement


The speed of a particle of mass [m] varies with the distance[x] as v(x)=ax^(-n). Assume v(x=0)=0 at t=0.
a)Find the force F(x) responsible
b)Determine x(t)
c)Determine F(t)

Homework Equations


The Attempt at a Solution


My solution to part a is F(x)=-ma^2nx^(-2n-1).

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
F=m(dv/dt), not what you did.
 
Thats how i got to my answer for part a. I started with that and solved it to get F(x)=-ma^2nx^(-2n-1). This answer was also in the back of my book. I am stuck on part b and c.
 
The a in your first formula is not the acceleration.
It is just an arbitrary constant.
 
I know this already too. I put in "a" because I don't have a way to put in alpha.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top