Mathematica Newtons cooling law DE, mathematical approach

[Pengwuino]

I have this one problem dealing with Newton's law of cooling:

\frac{{dT}}{{dt}} = - k(T - A)

I'm basically trying to determine at what time someone died! The info I have is that at time of death, the temperature was 98.6 degrees, at 10 AM it was at 92 degrees, and at 2PM it was at 86 degrees. The surrounding temperature, A, was 78 degrees and constant. Unfortunately, the book does not give an example as to how this DE works.

I have a feeling I need to do this:

\frac{{dT}}{{(T - 78)}} = - kdt

And integrate it… but I'm not sure how I would do that… especially with it just being k*dt. Any suggestions?

 

[HallsofIvy]

What? you have a problem with kdt? What is the integral of a constant?

If dT/(T-78), try a simple substitution: let u= T- 78 so du= dT. Can you integrate du/u??

 

[benorin]

\int\frac{{dT}}{{(T - 78)}} = - k\int dt\Rightarrow\ln (T - 78) = - kt+C

 

[arildno]

Well, your approach looks perfectly fine to me.
Alternatively, you could introduce the the dependent variable u(t)=T(t)-A,
and recognizing that u obeys the diff. eq \frac{du}{dt}=-ku
whereby you see that we have:
u(t)=Ce^{-kt}\to{T}(t)=A+Ce^{-kt}
If you let t=0 correspond to 10 AM, then you can determine C and k from the info known at that time, along with the info known at 2P.M.
Finally, use the info about the body temp. at time of death to determine when he died.

 

[Pengwuino]

I got to the second line benorin stated and now I am stuck again... I feel I need to find 'k' but I don't have an initial condition to work with, only a time change...

 

[Pengwuino]

u(t)=Ce^{-kt}\to{T}(t)=A+Ce^{-kt}
If you let t=0 correspond to 10 AM, then you can determine C and k from the info known at that time, along with the info known at 2P.M.
Finally, use the info about the body temp. at time of death to determine when he died.

Oh so are you trying to say I could use 10:00AM as a t=0 and simply use the negative value (would I get a negative value?) to determine how long before 10:00am he died?

 

[arildno]

Yup!

And yes, you'll get a negative value.

 

[Pengwuino]

Ahhhh there we go! -2.75 hours later... so 7:14am!