- #1
jillime
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A car which is originally at rest accelerates down a road with a net force of 32000 N acting on a 1980 kg car. At t = 12 seconds the driver slams on the brakes to avoid hitting a deer. Calculate the distance traveled by the car.
Coefficient of kinetic friction for the rubber on pavement is assumed to be .8
F⃗ net=ΣF⃗ =ma⃗ (a = F/m)
fk=μkN
v=v0+at
x=x0+v0t+(1/2)at2
v2=v20+2aΔx
a = Δv/Δt
blablahblah
Anyone who can tell me how to start this problem?
FBD shows force of friction going -X, normal force y, weight -y.
32000 = 1980a
a = 16.16 m/s2
v = 0 + 16.16x12
v = 193.92 m/s
I obviously have to do a second xvat for t=12 seconds and onward. These net force/ Newtons laws problems are killing me because they involve a lot of creativity with choosing working equations, which I don't have.
Help please!
Coefficient of kinetic friction for the rubber on pavement is assumed to be .8
F⃗ net=ΣF⃗ =ma⃗ (a = F/m)
fk=μkN
v=v0+at
x=x0+v0t+(1/2)at2
v2=v20+2aΔx
a = Δv/Δt
blablahblah
Anyone who can tell me how to start this problem?
FBD shows force of friction going -X, normal force y, weight -y.
32000 = 1980a
a = 16.16 m/s2
v = 0 + 16.16x12
v = 193.92 m/s
I obviously have to do a second xvat for t=12 seconds and onward. These net force/ Newtons laws problems are killing me because they involve a lot of creativity with choosing working equations, which I don't have.
Help please!