- #1

jillime

- 7

- 0

Coefficient of kinetic friction for the rubber on pavement is assumed to be .8

F⃗ net=ΣF⃗ =ma⃗ (a = F/m)

fk=μkN

v=v0+at

x=x0+v0t+(1/2)at

^{2}

v

^{2}=v

^{2}0+2aΔx

a = Δv/Δt

blablahblah

Anyone who can tell me how to start this problem?

FBD shows force of friction going -X, normal force y, weight -y.

32000 = 1980a

**a = 16.16 m/s**

^{2}v = 0 + 16.16x12

**v = 193.92 m/s**

I obviously have to do a second xvat for t=12 seconds and onward. These net force/ Newtons laws problems are killing me because they involve a lot of creativity with choosing working equations, which I don't have.

Help please!