A car which is originally at rest accelerates down a road with a net force of 32000 N acting on a 1980 kg car. At t = 12 seconds the driver slams on the brakes to avoid hitting a deer. Calculate the distance traveled by the car. Coefficient of kinetic friction for the rubber on pavement is assumed to be .8 F⃗ net=ΣF⃗ =ma⃗ (a = F/m) fk=μkN v=v0+at x=x0+v0t+(1/2)at2 v2=v20+2aΔx a = Δv/Δt blablahblah Anyone who can tell me how to start this problem? FBD shows force of friction going -X, normal force y, weight -y. 32000 = 1980a a = 16.16 m/s2 v = 0 + 16.16x12 v = 193.92 m/s I obviously have to do a second xvat for t=12 seconds and onward. These net force/ newtons laws problems are killing me because they involve a lot of creativity with choosing working equations, which I don't have. Help please!