Newton's Laws of Motion Question

AI Thread Summary
The discussion revolves around calculating the acceleration of a cart connected to a hanging mass via a pulley. The total force acting on the system is determined by subtracting the gravitational force of the hanging mass from that of the cart, resulting in a net force of 12N. Using Newton's second law (F=ma), the acceleration of the cart is calculated as 8 m/s² downward, while the acceleration of the hanging mass is calculated as 40 m/s². The importance of drawing free body diagrams is emphasized to better understand the forces and tension in the system. This approach helps clarify the relationship between the two masses and their shared acceleration.
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Homework Statement


A cart of mass 1.5 kg is connected by a string over a pulley to a hanging mass of 300g. What would be the acceleration of the cart and mass if the force of gravity is approximately 1N for a 100g mass.
Cart 1=1.5kg
Cart 2=0.3 Kg
Fg1=15N
Fg2=3N

Homework Equations



F=ma

The Attempt at a Solution


So I am having a bit of difficulty picturing this problem in my mind but here is my solution. I need to find the variables F,M, and a. So F would be 15-3=12N because the cart 1 needs to overpower the 3N in order to move it up. The weight would be 1.5kg so i would plug that into the equation to get 12/1.5=8m/s^2(Down). I could do the other one as well 12/0.3=40m/s^2. I was wondering if this is correct?
 
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Hi I <3 Physic, Welcome to Physics Forums.

I <3 Physic said:

Homework Statement


A cart of mass 1.5 kg is connected by a string over a pulley to a hanging mass of 300g. What would be the acceleration of the cart and mass if the force of gravity is approximately 1N for a 100g mass.
Cart 1=1.5kg
Cart 2=0.3 Kg
Fg1=15N
Fg2=3N

Homework Equations



F=ma

The Attempt at a Solution


So I am having a bit of difficulty picturing this problem in my mind but here is my solution. I need to find the variables F,M, and a. So F would be 15-3=12N because the cart 1 needs to overpower the 3N in order to move it up. The weight would be 1.5kg so i would plug that into the equation to get 12/1.5=8m/s^2(Down). I could do the other one as well 12/0.3=40m/s^2. I was wondering if this is correct?
The problem setup is a cart on a level surface (like a table top) connected by a string which goes over a pulley to some mass that's hanging from the string. So only one of the masses involved is subject to the force of gravity affecting the tension in the string.

You'll want to draw free body diagrams (FBDs) for both objects. The string remains taught with some tension T acting on both objects. You should be able to use the FBD to write expressions for the acceleration of both of them with the tension T as a shared variable (the tension in the string is the same for both objects).
 
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