Newton's Laws question : On springs and pulley system

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The discussion focuses on the conditions required for a particle attached to a spring on a rough inclined plane to oscillate. It establishes that the coefficient of friction must be less than one-third of the tangent of the incline angle (μ < 1/3 tan θ) for oscillation to occur. If friction dissipates all the energy before reaching equilibrium, defined as x_e = mg(sin θ + μ cos θ)/k, oscillation will not happen. The equilibrium condition is derived from the balance of forces, leading to the inequality μ(mg cos θ)x_e < (1/2)k(x_e)^2 + mg(x_e sin θ). The analysis emphasizes the critical interplay between friction, incline angle, and spring constant in determining the motion of the particle.
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A Particle is attached by a string to a point in a rough inclined plane of elevation \theta. Co-efficient of friction is \mu. Originally, the string is unstretched and lay along the line of greatest slope.Prove that the condition for particle to oscillate is \mu < 1/3tan\theta.
Note : Tension in the string = \lambda.\Deltal/l
\Deltal = Change in length
l = Original length
 
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If friction steals away all the energy of the particle before it reaches at most an equilibrium position of x_e=\frac{mg(sin \theta +\mu cos\theta)}{k}, where xe is the distance from the starting position of the particle and k is the spring constant, then there is no oscillation. The equilibrium position is gotten by solving:
mgsin \theta +\mu (mg cos\theta)-kx_e=0
Then solve:
\mu (mg cos\theta) x_e&lt;\frac{1}{2}k (x_e)^2+mg (x_e sin \theta)
by substituting in the expression for xe to get the condition for oscillation.
 
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