Newtons laws/weight/acceleration/force

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To achieve a true weight that is one-fourth of the weight on Earth's surface, one must ascend to a height of 3 times the Earth's radius (3r). This conclusion is derived from the gravitational force formula, which indicates that weight decreases with the square of the distance from the center of the Earth. The original poster expresses uncertainty about their intuition regarding the answer, indicating a struggle with understanding the concepts of weight and gravitational force. Additional assistance is requested for a second question, which remains unspecified. Clarifying these concepts is essential for mastering physics principles related to force and acceleration.
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Homework Statement



Please help I'm terrible with physics =[

1) If r is the radius of the Earth, how far above the surface of the Earth would you have to go so that your true weight is one-fourth of what it is on the surface of the Earth?

a) r
b) 2r
c) 3r
d) 4r

The only formulas I was given are in the attachment

Also I need help another question also in the attachment. Sorry if the picture is blurry that's the best I could make it. 1) For the first question my intuition tells me its 4 but I'm not 100% sure.
2) I am literally clueless for the second one
 

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