Newtons Method Problem

  • #1
1,009
0
Question:
Use Newtons method to approximate the indicated root of the equation correct to six decimal places.

The positive root of sin(x) = x^2

The answer is ...0.876726

Why did they pick this when the obvious root is 0?

Sin(0) = (0)^2 = 0
 
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  • #2
There are two roots - they want you to find the other one.
The one that it actually helps to use Newton's method for.
 
  • #3
Yes, they wouldn't ask you to use Newton's Method if they only wanted the trivial root. Try to start with a first approximation that is near the root. I'd try 1.
 

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