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Newton's Second Law & Moment of Inertia Derivation?

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data
    We did something very similar to this in lab

    http://webenhanced.lbcc.edu/physte/phys2ate/2A LAB HANDOUTS/Moment of Inertia.pdf

    Use Newton's Second to derive the expression for the experimentally determined moment of inertia


    2. Relevant equations
    Newton's Second Law is F=m*a

    s=(1/2)*a*t^2

    Experimentally Moment of Inertia

    I=r^2(m((gt^2/2s)-t) - mf)

    Trying to get to this ^

    mf= mass effective not much meaning just mass in kg
    If it confusing the gt^2 is divided by 2s then it is subtracted by t and multiplied by r^2 and then minus mf

    Torque= F*r= m*r*a

    T= (mf + m)(g - a) = tension

    3. The attempt at a solution

    T= (mf + m)(g - (2*s/t^2))

    T= (mf + m)((1/2)(a*t^2) - a)

    T= (mf + m)(a((1/2)*t^2 - 1)

    I am stuck write here
     
  2. jcsd
  3. Mar 29, 2009 #2

    Pythagorean

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    Gold Member

    Is calculus is a prerequisite for this course?
     
  4. Mar 29, 2009 #3
    yes it is Physics Calculus Based 2211K
     
  5. Mar 29, 2009 #4

    Pythagorean

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    Gold Member

    Calc may not be necessary.

    So what's the physical system you're doing in this problem? Is it the same exact system as in the lab?
     
  6. Mar 29, 2009 #5
    yes it is the exact same system
     
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