Newton's Third Law and Relativity

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SUMMARY

This discussion analyzes the implications of Newton's Third Law in the context of relativistic particle interactions, specifically between a proton and a moving electron. When the electron approaches the proton at a relativistic speed (with gamma = 2), the electric field generated by the electron is altered, resulting in a weaker force acting on the proton compared to when the electron is stationary. The calculations demonstrate that the force experienced by the proton is F = (1/4)(q^2/r^2), while the force on the electron, according to the Lorentz force law, remains F = (q^2/r^2). This discrepancy highlights that while Newton's Third Law appears violated, momentum conservation is maintained when considering the momentum of both particles and the electromagnetic fields.

PREREQUISITES
  • Understanding of relativistic physics, specifically Lorentz transformations.
  • Familiarity with electric fields and forces, particularly Coulomb's law.
  • Knowledge of the Lorentz force law and its application in electrodynamics.
  • Basic concepts of momentum conservation in physics.
NEXT STEPS
  • Study the implications of Lorentz transformations on electric and magnetic fields.
  • Explore the concept of momentum conservation in electromagnetic fields.
  • Learn about the role of electromagnetic fields in particle interactions.
  • Investigate advanced topics in electrodynamics, such as the Poynting vector and field momentum.
USEFUL FOR

Physicists, students of advanced physics, and anyone interested in the intersection of classical mechanics and electromagnetism, particularly in understanding relativistic effects on particle interactions.

psholtz
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Suppose I have a proton at the origin, and a (stationary) electron on the x-axis at x=r.

Taking q to be the elementary charge, the force acting on each of these particles is:

[tex]F = \frac{q^2}{r^2}[/tex]

Now suppose that the electron is heading towards the proton (in the negative x-direction) at a relativistic speed. Suppose gamma=2. The field generated by the electron will be "squished" in the x-direction, and correspondingly the force experienced by the proton will be weaker than it would have been had the electron been stationary.

The electric field generated by a moving charge (as seen in the "stationary" frame) is given by:

[tex]E = \frac{Q}{r^2}\frac{1-\beta^2}{1-\beta^2\sin^2\theta}[/tex]

where Q is the charge on the moving particle and theta is the angle between the origin of the moving particles coordinate frame and the direction of the particle's motion (in this case, the x-axis).

In our case, we have:

[tex]E = \frac{1}{4}\frac{q}{r^2}[/tex]

and so the force the proton experiences, due to the moving electron, is given by:

[tex]F = \frac{1}{4}\frac{q^2}{r^2}[/tex]

Meanwhile, the force on the (moving) electron, due to the stationary proton, is given by the Lorentz force law:

[tex]F = qE + \frac{1}{c}v \times B[/tex]

Since the proton doesn't generate a magnetic field, the force on the (moving) electron due to the stationary proton, at the moment the electron is passing the point x=r, is:

[tex]F = \frac{q^2}{r^2}[/tex]

In other words, the force the proton imparts to the electron is 4x the force that the electron imparts to the proton.

What happened to Newton's Third Law?
 
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Newton's Third Law is equivalent to conservation of momentum. In electrodynamics, the total momentum of a particles in the system is generally not conserved. However, electric and magnetic fields also carry momentum. The total momentum of the particles and the fields is conserved.
 
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