No idea where to start for linear transformation question from P2->P2

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To find the matrix representation of the linear transformation T: P2 → P2 with respect to the standard basis B = {1, x, x^2}, the polynomials must be expressed as column vectors. Each polynomial's coefficients correspond to the components of the vectors, such as T(x-1) = -1, 1, 0 resulting in the vector (-1, 1, 0). The transformation can be represented in matrix form as TA = B, where A consists of the column vectors from the left-hand side and B from the right-hand side. The solution for T can then be obtained by multiplying both sides by the inverse of A, leading to T = BA^-1. Understanding the representation of polynomials as vectors is crucial for this process.
jra0718
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Let T:P2\rightarrowP2 be given by

T(x-1)=1-x
T(x2-2x)=-1+x-2x2
T(3-x2)=-1+2x+3x2

Find the matrix for T with respect to the standard basis B={1,x,x2}for P2

To be honest, I have no idea where to start. Help would be greatly appreciated
 
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Write the polynomials as column vectors like
x-1 --->
-1,
1
0
x^2-2x --->
0
-2
1

and so on and make a matrix A from the three columns on the left hand side of the equation and a matrix B from the columns at the right-hand side. You get a matrix equation TA=B which you can solve for T
by multiplying both sides with the inverse of A:
T=TA A-1=BA-1.

ehild
 
i don't understand how you got the column vectors
 
1, x, x^2 are the basis, consider them as base vectors e1, e2, e3. The coefficient of x^k in the polynomial is considered as the k-th component.

For example, -1+x-2x^2 = -1 (1) +1 (x) -2 (x^2) or -1 e1 +1*e2 -2 e3. You can write it as the vector (-1,1,-2), or its transposed as column vector.

ehild
 
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