No prefix: How far does a car move before running out of gas on a road?

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SUMMARY

A car moving at 45 km/hr takes 6.0 seconds to come to a stop after running out of gas. The initial calculation using the equation x=(vi+vf)/2 * t resulted in 135 meters, which is incorrect. The correct distance is 37.5 meters, achieved by converting the velocity from km/hr to m/s before applying the formula. The conversion is essential for accurate results in physics problems involving motion.

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Homework Statement


A car is moving down a road at 45 km/hr when it runs out of gas. How far does the car move if it takes 6.0s to roll to a stop?

Homework Equations


x=(vi+vf)/2 *t I tried this equation, but I got the answer of 135 m. It says the answer is 37.5 m in the answers given by the teacher.

The Attempt at a Solution



I set it up this way:

vi: 45 km/hr
vf: 0
t= 6.0 s
x=?
x= (45+0)/2 * 6.0 = 135 mI want to know what I'm doing wrong, am I using the wrong equation? Thanks.
 
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ArcherofScience said:

Homework Statement


A car is moving down a road at 45 km/hr when it runs out of gas. How far does the car move if it takes 6.0s to roll to a stop?


Homework Equations


x=(vi+vf)/2 *t I tried this equation, but I got the answer of 135 m. It says the answer is 37.5 m in the answers given by the teacher.

The Attempt at a Solution



I set it up this way:

vi: 45 km/hr
vf: 0
t= 6.0 s
x=?
x= (45+0)/2 * 6.0 = 135 m

I want to know what I'm doing wrong, am I using the wrong equation? Thanks.
I suspect that you need to convert the velocity to m/sec.
 


yeh it worked, i got the right answer ! :approve: :D

thankyou! :)
 

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