- 8,943
- 2,954
GAsahi said:The answer IS correct.
But your reasoning was incorrect.
GAsahi said:The answer IS correct.
stevendaryl said:The easiest way to see this is in the case of two identically accelerating rockets in flat spacetime, each equipped with an onboard clock. Using an inertial coordinate system, the ratio of the rates will be 1, because the time dilation effects will be the same for both clocks. Using the Rindler coordinate system in which the rear rocket is at rest, the front clock will be seen to be running faster than the rear clock.
stevendaryl said:But your reasoning was incorrect.
stevendaryl said:Let me do an explicit calculation to prove my point.
In Rindler coordinates (X,T), we have two clocks, one at X = X1, and one at X2. The Rindler interval is:
d\tau2 = X2 dT2 - dX2
So for clocks at rest in the X,T coordinates, we have:
d\tau = X dT
So the ratio of the rates is: d\tau1/d\tau2 = X1/X2
Conclusion: the "higher" clock (with greater X) runs faster.
Now, do the same calculation in the coordinate system (x,t) related to (X,T) through:
x = X cosh(gT)
t = X/c sinh(gT)
So d\tau2 = dt2 - 1/c2 dx2
= dt2 (1 - v2/c2)
where v = dx/dt = the speed of the clock. So
d\tau = \sqrt{1-(v/c)^{2}} dtThe ratios of the rates in this coordinate system is given by:
d\tau1/d\tau2 = \sqrt{1-(v_{1}/c)^{2}}/\sqrt{1-(v_{2}/c)^{2}}
At t=0, v_{1} = v_{2} = 0. So the ratio starts off equal to 1, not X1/X2.
At t=0, v_{1} = v_{2} = 0. So the ratio starts off equal to 1, not X1/X2.
stevendaryl said:Let me do an explicit calculation to prove my point.
In Rindler coordinates (X,T), we have two clocks, one at X = X1, and one at X2. The Rindler interval is:
d\tau2 = X2 dT2 - dX2
So for clocks at rest in the X,T coordinates, we have:
d\tau = X dT
So the ratio of the rates is: d\tau1/d\tau2 = X1/X2
Conclusion: the "higher" clock (with greater X) runs faster.
GAsahi said:This derivation is correct.
stevendaryl said:Now, do the same calculation in the coordinate system (x,t) related to (X,T) through:
x = X cosh(gT)
t = X/c sinh(gT)
So d\tau2 = dt2 - 1/c2 dx2
= dt2 (1 - v2/c2)
where v = dx/dt = the speed of the clock. So
d\tau = \sqrt{1-(v/c)^{2}} dt
The ratios of the rates in this coordinate system is given by:
d\tau1/d\tau2 = \sqrt{1-(v_{1}/c)^{2}}/\sqrt{1-(v_{2}/c)^{2}}
At t=0, v_{1} = v_{2} = 0. So the ratio starts off equal to 1, not X1/X2.
GAsahi said:This part of the derivation is in error. If you did it correctly, you would have gotten that the correct result is \frac{d \tau_1}{d \tau_2}=\sqrt{\frac{1-v/c}{1+v/c}} where v is the instantaneous speed of the rocket containing the two clocks wrt the launcher frame.
I can get into all the details of why the above is the correct result but I won't , the way to get the correct result is not simply using the equations of hyperbolic motion, you can simply use the equivalence principle and to observe the Doppler effect on the frequency emitted at one end of the rocket and received at the other end, the two ends being separated by a distance h=X_1-X_2. The bottom line is that there is always motion between the two ends of the rocket, so you cannot write
It would appear that if stevendaryl's calculation of relative rate as the relationship between instantaneous gammas is incorrect then a basic principle of SR falls. Specifically the Clock Hypothesis. Delta t' for either clock must be equal to an integration over that worldline interval based on instantaeous (infinitesimal) velocity gammas ,yes?At t=0, v_{1} = v_{2} = 0. So the ratio starts off equal to 1, not X1/X2.
At t=0, v_{1} = v_{2} = 0. So the ratio starts off equal to 1, not X1/X2.
How could it not start out at At t=0, v_{1} = v_{2} = 0 ? it does not instantaneously attain its final proper acceleration ,yes?? It would seem it would have to start out at 1 and over some finite time interval reach the relative ratio.GAsahi said:If the above were true, you would have found a way of disproving the principle of equivalence.
Austin0 said:How could it not start out at At t=0, v_{1} = v_{2} = 0 ? it does not instantaneously attain its final proper acceleration ,yes?? It would seem it would have to start out at 1 and over some finite time interval reach the relative ratio.
It would appear that if stevendaryl's calculation of relative rate as the relationship between instantaneous gammas is incorrect then a basic principle of SR falls. Specifically the Clock Hypothesis. Delta t' for either clock must be equal to an integration over that worldline interval based on instantaeous (infinitesimal) velocity gammas ,yes?
GAsahi said:The measured ratio is X_1/X_2=\sqrt{\frac{1-v/c}{1+v/c}}, not 1 and, definitely NOT \sqrt{\frac{1-(v_1/c)^2}{1-(v_2/c)^2}}.
GAsahi said:This part of the derivation is in error. If you did it correctly, you would have gotten that the correct result is \frac{d \tau_1}{d \tau_2}=\sqrt{\frac{1-v/c}{1+v/c}} where v is the instantaneous speed of the rocket containing the two clocks wrt the launcher frame.
GAsahi said:You missed the point that he got the wrong answer.
PeterDonis said:It looks to me like these two quantities refer to two different things. The first refers to Schwarzschild spacetime; the second refers to Rindler coordinates on Minkowski spacetime. The answers for those two cases will not be the same, because Schwarzschild spacetime is curved and Minkowski spacetime is flat.
stevendaryl said:That's exactly the point: your method of computing redshift gives the wrong answer unless two conditions are met:
(1) You are using a coordinate system in which the metric components are independent of time, and
(2) You are using a coordinate system in which the sender and the receiver of the light signals are both at rest in that coordinate system.
stevendaryl said:That was exactly my point: You can't compute redshift by just computing d\tau1 in terms of dx and dt, computing d\tau2 in terms of dx and dt, and dividing them.
GAsahi said:The two approaches need to produce the SAME answer, otherwise he's found a way to disprove EPE.
PeterDonis said:It looks to me like these two quantities refer to two different things. The first refers to Schwarzschild spacetime; the second refers to Rindler coordinates on Minkowski spacetime. The answers for those two cases will not be the same, because Schwarzschild spacetime is curved and Minkowski spacetime is flat.
GAsahi said:This is standard textbook stuff, I have given you a couple of links that contradict your statement.
stevendaryl said:The two ratios are only the same for a special coordinate system in which (1) the components of the metric tensor are time-independent,
and (2) the two clocks are at rest in that coordinate system.
GAsahi said:Actually, IF you do the calculations correctly and IF you apply the EPE correctly, they ARE the same, with a very high degree of precision. EPE tells you that they must be the same. Attached please see the complete calculations.
stevendaryl said:No, they are not the same, to a high degree of precision. They are different ratios: One is a ratio of clock rates, as measured in the "launch" frame. The other is the ratio of frequencies for a light signal. Those two ratios are NOT the same.
GAsahi said:Actually, IF you do the calculations correctly and IF you apply the EPE correctly, they ARE the same, with a very high degree of precision. EPE tells you that they must be the same. Attached please see the complete calculations.
GAsahi said:No. I have already corrected you on this statement. IF it were true (it isn't) the GPS calculations would not work. Please see the N.Ashby paper in Living Reviews as reference.
stevendaryl said:What your enclosed calculations show is that the ratio of clock rates (which is computed in the first calculation using Schwarzschild coordinates) gives the same answer as the redshift formula (computed in the second calculation using Doppler shift). I'm AGREEING with that.
But--and I've already said this several times--if you use special coordinates in which (1) the metric is independent of time, and (2) the sender and receiver are at rest in that coordinate system, then for that particular coordinate system, the two answers are the same.
Your calculations are not contradicting those claims, they are illustrating them. If instead of using the Schwarzschild coordinates to compute relative clock rates, you had used a different coordinate system to compute relative clock rates, you would have gotten a different answer. I showed you that, by using inertial coordinates to compute relative clock rates for accelerating clocks.
GAsahi said:Incorrect. A simple disproof can be found in the way N.Ashby does the computations explaining the GPS functionality (see his paper in Living Reviews). The receiver and the emitter are NOT at rest wrt each other.
stevendaryl said:GPS calculations are done in a very specific coordinate system; most likely Schwarzschild coordinates, since that's the most convenient for an approximately spherically symmetrical case. In Schwarzschild coordinates, it IS the case that the redshift formula between two observers at rest (say, one at the bottom of a mountain, and one at the top of a mountain) will be equal to the ratio of clock rates.
stevendaryl said:When they are NOT at rest wrt each other, the redshift formula is NOT the same as the ratio of the clock rates. The redshift differs from this rate by a Doppler correction. They explicitly say that in the Wikipedia article about Pound-Rebka:
Special Relativity predicts a Doppler redshift of :
f_r=\sqrt{\frac{1-v/c}{1+v/c}}f_e
On the other hand, General Relativity predicts a gravitational blueshift of:
f_r=\sqrt{\frac{1-\dfrac{2GM}{(R+h)c^2}}{1-\dfrac{2GM}{Rc^2}}}f_e
The detector at the bottom sees a superposition of the two effects.
GAsahi said:Then what are you splitting hairs about?
Your second condition is false , as shown by the way the GPS calculations are being done. I have already pointed this to you three times. The emitter and the receiver are in motion wrt each other, yet the calculations hold.
It is not clear what mistake you made
... but I get the SAME result through both methods. If your claims were true the GPS calculations would fail.
GAsahi said:You misread the wiki paper: it tells you that the way to measure the gravitational effect is by cancelling it with the appropriate amount of Doppler effect by moving the source wrt the detector at the appropriate speed.
GAsahi said:The emitter and receiver are NOT at rest wrt each other. The calculations done using Schwarzschild coordinates are confirmed by practice. So, your second claim is false.
stevendaryl said:Because you are making a serious mistake in confusing two different things:
(1) The ratio of clock rates, and (2) the redshift formula. They are not the same, except in special circumstances.
stevendaryl said:No, both are about flat spacetime.
stevendaryl said:My point is that the redshift formula is NOT the same as the ratio of clock rates, except in very specific circumstances. Those circumstances actually hold for Rindler coordinates and for Schwarzschild coordinates, but they don't hold for arbitrary coordinates.
stevendaryl said:The conditions for being able to equate "relative clock rates" with "redshift" are: (1) The metric tensor is independent of time, and (2) the sender and receiver are at rest in the coordinate system.
stevendaryl said:If the detector and the emitter are not at rest relative to each other (as measured in Schwarzschild coordinates) then the pure position-dependent gravitational time dilation must be corrected by an additional Doppler term. Are you disputing that? That's very bizarre. Think about it: suppose that the receiver and the sender are at the SAME height. Then the redshift is purely due to Doppler.
You CAN'T use the gravitational time dilation to compute redshift without including Doppler, except in the special case in which the sender and receiver are at rest (so that the Doppler effect is zero). You're not seriously disputing that, are you?