No, this is not correct. See my previous post.

AI Thread Summary
To determine the net force required to stop a 1200 kg truck traveling at 22 m/s over 330 meters, the calculations involve finding the necessary deceleration. The initial attempt at calculating time and acceleration is flawed, as the equation used assumes constant velocity. Instead, the correct approach involves using kinematic equations to relate distance, initial velocity, final velocity, and acceleration. The cause of the net force is confirmed to be friction from the brakes. Understanding energy conservation principles may also aid in solving the problem effectively.
James Prado
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Homework Statement


A truck (1200kg) is traveling south at 22m/s
a) what is the net force required to bring the truck to a stop in 330m?
b) what is the cause of this net force? (im assuming the answer is friction due to brakes)

Mass= 1200kg (1.2*10^4)
Velocity= 22m/s [south]
What force is required to stop the object (1200kg) in 330 meters?

Homework Equations


[/B]
anything needed to solve the equation?

The Attempt at a Solution



ΣF= m*a
=1200kg * a

a= ( 22 m/s [south] ) / Δt

330m/22m= Δt
t=15 seconds

a= 22/15
a = 1.4666667

"a" is now the number of meters per second required to decelerate to reach fnet = 0 ?

Unsure if this is on the right track or extremely off what I need to do for a question like this
 
Last edited:
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(a) Think energy conservation. Kinetic energy change to heat.
(b) you're right.
 
James Prado said:

Homework Statement


A truck (1200kg) is traveling south at 22m/s
a) what is the net force required to bring the truck to a stop in 330m?
b) what is the cause of this net force? (im assuming the answer is friction due to brakes)

Mass= 1200kg (1.2*10^4)
Velocity= 22m/s [south]
What force is required to stop the object (1200kg) in 330 meters?

Homework Equations


[/B]
anything needed to solve the equation?

The Attempt at a Solution



ΣF= m*a
=1200kg * a

a= ( 22 m/s [south] ) / Δt
OK up to here.

330m/22m= Δt
t=15 seconds
##x = vt## only works when there's no acceleration.

a= 22/15
a = 1.4666667

"a" is now the number of meters per second required to decelerate to reach fnet = 0 ?

Unsure if this is on the right track or extremely off what I need to do for a question like this
 

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