No Work Done on a Textbook: Explanation of Concept

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When carrying a textbook horizontally at a constant velocity, no work is done because the force applied (gravity) acts vertically while the displacement is horizontal. Work is defined as the product of force and displacement in the direction of the force, represented by the formula W = FΔs cos θ. Since the angle between the vertical force and horizontal displacement is 90 degrees, the cosine of 90 degrees is zero, resulting in no work being performed. If a horizontal force were applied in the same direction as the displacement, work would be done on the textbook. Understanding this relationship between force and displacement is crucial for grasping the concept of work in physics.
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1. Hey everyone! I am currently studying for my final exam and I am trying to review work to start out. When I was reading, it gave me an example of where a person is holding a textbook and the person moves the textbook in the horizontal direction. Under the picture they gave an explanation which says: No work is done on a textbook when carried in the horizontal direction at a constant velocity.



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3. Considering Work depends on displacement, I just thought that if you move a textbook up or down and that is displacement, then why can't there be displacement if you move the textbook (or anything) horizontally?
 
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Do you know the definition of "work"? I mean, do you know how to calculate it? What do you get if you use that formula to calculate the work performed moving a book horizontally?
 
From the site that I am reading from...Work is the "force-displacement product". The formula shows to be: W = FΔs cos θ
 
Ok...so is it because since there is a vertical force and the displacement is horizontal, then that's why work is not being done? So with that in mind, if there was a horizontal force and a horizontal displacement, then there would be work being done on the textbook?
 
Right. The ##\theta## in that formula is the angle between the force vector and the displacement vector. So when the force and the displacement are perpendicular, we have ##\cos\theta=\cos\frac\pi 2=0##. When they are parallel, we have ##\cos\theta=\cos 0=1##.
 
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Thank you so much!
 
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