Non 1-1 transformation of continuous random variable

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Kate2010
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Homework Statement



X is exponentially distributed with mean s.
Find P(Sin(X)> 1/2)

Homework Equations



fX(x) = se-sx, x[tex]\geq[/tex] 0
0, otherwise

FX(x) = 1 - e-sx, x[tex]\geq[/tex] 0
0 otherwise

The Attempt at a Solution



Let Y = sin X

FY (y) = P(Y[tex]\leq[/tex] y)
= P(sinX [tex]\leq[/tex] Y)
= P(X [tex]\leq[/tex] arcsin(y), X[tex]\geq[/tex] [tex]\pi[/tex] - arcsin(y)) {This is where I become slightly unsure}
=FX(arcsin(y)) - FX([tex]\pi[/tex] - arcsin(y))
=1-e-s(arcsin(y)) - (1-e-s([tex]\pi[/tex] - arcsin(y)))

From here I can differentiate to find the pdf and then use that to find sinX < 1/2.
 
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Any ideas anyone?