How can I solve (x^2)y'' - 2xy + 2y = (x^3)sinx ? I've used Euler-Caucy to find the homogeneous eq. (C1)e^x + (C2)e^2x. Then I've calculated the wronski (either e^3x or -e^3x depending on which function is y1 and y2). The rest involves solving the integral of xsin(x)/e^x and xsin(x)/e^2x, whics seems quite difficult. Am I on the right track?