Non spherical solutions of a spherical potential well?

nista
Messages
11
Reaction score
0
Hi all
just a question about the understanding of the solutions of a spherical potential well.
What is the physical sense of solutions which have no spherical symmetry?
I just would think that the probability of finding a particle
whose state is described by one of the eigenstate of the Hamiltonian should not depend on the angular coordinate as the
problem as spherical symmetry. However for solutions with angular momentum larger than 0 this not the case. Why?
Thanks in advance for your comments

Roberto
 
Physics news on Phys.org
If there is no preferred direction, so all the m values for each L are equally likely, the full probability distribution will be spherically symmetric. If there is a defined z axis for which different m values have different amplitudes, there will be an angular distribution.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top