# Non-Transcendental Numbers Def. What if we allow √14 as a coefficicie?

## Homework Statement

A non-transcendental number is one that's a root of a (non-constant) polynomial with rational coefficients.
Does allowing radicals as coefficients, eg: 5√3, 2^(1/3) get us any new different numbers?

## The Attempt at a Solution

1. In some cases we get no new numbers, eg:
$x^2+\sqrt{3}=0\Leftrightarrow x^6=3$

$x^2+x\sqrt{3}+\sqrt{2}=0\Leftrightarrow x^2+x\sqrt{3}=-\sqrt{2} \Rightarrow x^4+3x^2+2x^3\sqrt{3}=2 \Leftrightarrow x^4+3x^2-2=-2x^3\sqrt{3} \Rightarrow (x^4+3x^2-2)^2=4x^6 \times 3$

We solve this by isolating the radicalss and squaring/cubing/etc them. But with more coefficients it becomes harder. What about a 5th degree polynomials with only cubic radical coefficients?

So the question is:
-Do we get new non-trascendental numbers if we allow rational AND radicals as coefficients.
-Can we always turn a polynomial with radical coefficients into a one with rational coefficients?

PS: By radicals I mean just some number that's written with the nth-root symbol. Use whatever definition you feel fits best.

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dextercioby
Homework Helper

No, you can get rid of all the (finite nr. of) radicals after a finite number of raising to a suitable natural power, so that the definition of algebraic numbers is exhaustive.

No, you can get rid of all the (finite nr. of) radicals after a finite number of raising to a suitable natural power, so that the definition of algebraic numbers is exhaustive.
How exactly can you always just raise them to a suitable power without creating additional radicals to be solved?

Dick