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Norm of sqrt(i)

  1. Sep 23, 2011 #1
    Why is |sqrt(i)| = 1? (where i is the imaginary unit)

    I thought to find a norm you do sqrt(x^2 + y^2) so isn't it
    sqrt(0 + sqrt(i)^2)
    = sqrt(i)


    What am I doing wrong here?

    nvm, i got it...
  2. jcsd
  3. Sep 23, 2011 #2
    For anyone else reading this and curious about a similar issue, it is important that you recognize that y in the formula for the norm is simply the imaginary part of the complex number (which is real, of course).

    Of course, the other way to calculate the norm is to explicitly find [itex]i^{1/2}[/itex] and find the norm of this. You will find that it is the same.
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