Normal distribution modified by potential

friend
Messages
1,448
Reaction score
9
Normal distribution modified by "potential"

For a random process the distribution if described by a gaussian distribution. But if the process has components that throw off the normal distribution, can any distribution be described by a gaussian distribution with another function, call it a potential, in the exponent of the gaussian added to the squared term?
 
Last edited:
Physics news on Phys.org


friend said:
For a random process the distribution if described by a gaussian distribution.
You can cook up a stochastic process with any probability law you want

friend said:
But if the process has components that throw off the normal distribution, can any distribution be described by a gaussian distribution with another function, call it a potential, in the exponent of the gaussian added to the squared term?

This is related to your question http://en.wikipedia.org/wiki/Boltzmann_distribution
 
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Thread 'Detail of Diagonalization Lemma'
The following is more or less taken from page 6 of C. Smorynski's "Self-Reference and Modal Logic". (Springer, 1985) (I couldn't get raised brackets to indicate codification (Gödel numbering), so I use a box. The overline is assigning a name. The detail I would like clarification on is in the second step in the last line, where we have an m-overlined, and we substitute the expression for m. Are we saying that the name of a coded term is the same as the coded term? Thanks in advance.
Back
Top