Normal Force of a skateboarder at the bottom of a circular ramp

AI Thread Summary
To calculate the normal force on a skateboarder at the bottom of a circular ramp with a 3.75 m radius, one must consider both gravitational force and centripetal force. The skateboarder’s weight contributes to the normal force, which can be calculated using the equation F = mv^2/r after determining the speed at the bottom through energy conservation. The initial potential energy (mgh) converts to kinetic energy (1/2 mv^2), allowing for the calculation of velocity. The total normal force at the bottom is the sum of the gravitational force and the centripetal force required to keep the skateboarder moving in a circular path. Properly combining these forces yields the correct normal force value.
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A skateboard track has the form of a circular arc with a 3.75 m radius. A 47.0 kg skateboarder starts from rest at the top of the circular arc. What is the normal force exerted on the skateboarder at the bottom of the circular arc?
I tried using conservation of energy to solve for v
mgh=1/2 mv^2
and then I tried plugging that in for F=mv^2/r but it didn't work. How are you supposed to do this problem?
 
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The weight of the skateboarder is also part of the normal force.
 
So how do I factor that in with the other force equation?
 

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