Normalizing a wave packet - cannot understand the solution

  • Thread starter Thread starter physiker99
  • Start date Start date
  • Tags Tags
    Wave Wave packet
physiker99
Messages
36
Reaction score
0
This question is about normalizing a wave packet, this is actually the solution and I couldn't understand 2 points.

- I cannot see how the red encircled part do not diverge to infinity.

- And I cannot understand how the very last line is derived from the 2nd last one.

For the second one I tried to call i(po-px) as A and 1/(deltaX) B but that did not lead anywhere.

2ikwrw6.png
 
Physics news on Phys.org
For the red box
<br /> e^{i \alpha x - \beta x} = e^{i \alpha x}e^{-\beta x}<br />
for x -> infinity: the first term oscillates between 1 and -1 (in accordance with euler's equation), but the second term approaches zero. So the whole thing approaches zero, and you're just left with the evaluation at x = 0.And for the penultimate to ultimate lines, you just have to get a common denominator to combine the fractions; a bunch of stuff will cancel... you multiply through by delta X / delta X
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top