BruceG
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For some time I've been trying to get a geometric appreciation of why normed division algebras only exist in dimensions 1,2,4,8 (namely R,C,H,O).
As always Baez provides the most elegant answer:
http://math.ucr.edu/home/baez/octonions/node6.html"
Allow me to descibe the key point of the proof in case anyone has any better insight to add.
The "division" property of an algebra (ab=0 iff a=0 or b=0) gaurantees that multiplication by unit numbers generates all possible rotations of the unit sphere (e.g. any 2 points on a circle can be reached by rotation by a unit complex number).
From this Baez goes on to show that an n-dimensional normed division algebra must be an irreducible representation of the clifford algebra of dimension n-1.
The result can then be read from the following table:
n -> irreduclible rep of Cliff(n)
0 -> 1
1 -> 2
2 -> 4
3 -> 4
4 -> 8
5 -> 8
6 -> 8
7 -> 8
8 -> 16
9 -> 32
10 -> 64
11 -> 64
12 -> 128
13 -> 128
14 -> 128
15 -> 128
We see that the clifford algebras matrices rapidly become too large to allow the formation of a division algebra.
As always Baez provides the most elegant answer:
http://math.ucr.edu/home/baez/octonions/node6.html"
Allow me to descibe the key point of the proof in case anyone has any better insight to add.
The "division" property of an algebra (ab=0 iff a=0 or b=0) gaurantees that multiplication by unit numbers generates all possible rotations of the unit sphere (e.g. any 2 points on a circle can be reached by rotation by a unit complex number).
From this Baez goes on to show that an n-dimensional normed division algebra must be an irreducible representation of the clifford algebra of dimension n-1.
The result can then be read from the following table:
n -> irreduclible rep of Cliff(n)
0 -> 1
1 -> 2
2 -> 4
3 -> 4
4 -> 8
5 -> 8
6 -> 8
7 -> 8
8 -> 16
9 -> 32
10 -> 64
11 -> 64
12 -> 128
13 -> 128
14 -> 128
15 -> 128
We see that the clifford algebras matrices rapidly become too large to allow the formation of a division algebra.
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