Not enough information in this momentum question?

AI Thread Summary
The discussion revolves around solving a momentum problem involving two air track gliders in an elastic collision. For part A, participants note that to find the final velocities, one must know at least one rebound velocity, and they confirm that the conservation of momentum equation can be applied alongside the conservation of kinetic energy for elastic collisions. In part B, the calculation for the final velocity of the gliders sticking together is provided, yielding a velocity of -1.0 m/s. Additionally, the kinetic energy after the collision is calculated as 0.25 J. The conversation emphasizes the necessity of careful calculations and the importance of correctly applying the principles of momentum and energy conservation.
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Homework Statement


Two air track gliders of a mass 300 g and 200 g are moving towards each other in opposite directions with speeds of 50 cm/s and 100cm/s respectively. Take the direction of the more massive glider as positive.

A.) determine the velocity of each glider after the collision if the collision is elastic.

b.) The most inelastic collision would occur if the two gliders stuck together on impact. If this was the case, find the velocity of the pair after the collision, and the kinetic energy in standard units of "J".


Homework Equations


m1v1i +m2v2i = m1v1f + m2v2f


The Attempt at a Solution



a.) in order to find the unknown velocites you need to know at least one of the rebound velocities do you not?

0.3(0.50) + 0.2(-1.00) = 0.3v1f + 0.2v2f

b.)0.3(0.50) + 0.2(-1.00) = 0.5vf

vf = (0.15-0.2)/0.5
= -1.0 m/s

KE = 1/2mv^2

= 1/2(0.5)(-1.0)^2
= 0.25 J
 
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Is this elastic collision only one-dimensional?
 
physicskid72 said:

Homework Equations


m1v1i +m2v2i = m1v1f + m2v2f

The Attempt at a Solution



a.) in order to find the unknown velocites you need to know at least one of the rebound velocities do you not?

0.3(0.50) + 0.2(-1.00) = 0.3v1f + 0.2v2f

You have enough information to solve it (given that this is a 1 dimensional problem -- things can get more complicated if the objects can freely move in more than 1 dimension).

You have the conservation of momentum equation that you listed above. But since you are assuming it is a perfectly elastic collision, you can also use conservation of kinetic energy (conservation of kinetic energy only applies if the collision is perfectly elastic). So you have 2 equations and 2 unknowns, which is solvable.

b.)0.3(0.50) + 0.2(-1.00) = 0.5vf

vf = (0.15-0.2)/0.5
= -1.0 m/s

Try that last calculation again. I think you missed a decimal point somewhere.
 
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