Not sure how to do 2 body problem

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The discussion focuses on solving a physics problem involving two masses, one on an inclined plane and the other hanging from a pulley. The user expresses confusion about the derivation of the acceleration formula and their calculations, particularly regarding the forces acting on each mass. There is a suggestion to account for dynamic friction acting on the mass on the ramp and to draw Free Body Diagrams for clarity. The conversation emphasizes the importance of identifying all forces and writing equations for each mass to find their shared acceleration accurately. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


Look below for diagram

Mass m1is on an inclined plane and weighs 1.00 kg. The inclined plane creates a 40.0 degree angle with the ground, and μk = 0.225. Mass m11 is attached to a weight hanging off the edge via pulley, called M2. M2 has a mass of 1.50kg and hangs from a height h of 50.0 cm. When the system is released from rest, how long will it take M2 to hit the floor? Assume the static frction is exceeded by the weight of M2

Homework Equations


d=1/2(a)(t2)
f=ma (or f = mg)
f1 = MgSin∅
f2 = mg
a = net force/net weight
a = (m2g-m1gsin∅)/(m1+m2) - not sure how this was derived, was in my book

The Attempt at a Solution


a=(1.5 kg ) (9.8 m/s2)-(1 kg ) (9.8 m/s2) sin(40)
(1 kg )+(1.5 kg )

This solution feels wrong and I'm very sure I did it wrong. Please look it over for me; I'm terribly confused by this problem.
 

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Sorry for bumping but still looking for help on this
 
yesiammanu said:

Homework Statement


Look below for diagram

Mass m1is on an inclined plane and weighs 1.00 kg. The inclined plane creates a 40.0 degree angle with the ground, and μk = 0.225. Mass m11 is attached to a weight hanging off the edge via pulley, called M2. M2 has a mass of 1.50kg and hangs from a height h of 50.0 cm. When the system is released from rest, how long will it take M2 to hit the floor? Assume the static frction is exceeded by the weight of M2


Homework Equations


d=1/2(a)(t2)
f=ma (or f = mg)
f1 = MgSin∅
f2 = mg
a = net force/net weight
a = (m2g-m1gsin∅)/(m1+m2) - not sure how this was derived, was in my book

The Attempt at a Solution


a=(1.5 kg ) (9.8 m/s2)-(1 kg ) (9.8 m/s2) sin(40)
(1 kg )+(1.5 kg )

This solution feels wrong and I'm very sure I did it wrong. Please look it over for me; I'm terribly confused by this problem.

What happened to the dynamic friction between the first mass and the ramp?

List all the forces acting on the individual masses, then draw a Free Body Diagram for each. From that you should be able to write equations pertaining to each body and solve for their shared acceleration.
 
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