Not sure how to start this problem hint please

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To determine the tension in the line holding the helium-filled balloon, one must consider the forces acting on it: the weight of the balloon, the buoyant force from the displaced air, and the tension in the line. The buoyant force can be calculated using the formula B = density(fluid) x volume(fluid) x g, where the fluid is air. The volume of the balloon can be derived from its radius, and the weight of the helium-filled balloon must also be accounted for. Ultimately, the tension in the line is equal to the difference between the buoyant force and the weight of the balloon. Understanding these forces is crucial for solving the problem accurately.
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An empty rubber balloon has a mass of 0.0135 kg. The balloon is filled with helium at a density of 0.181 kg/m3. At this density the balloon is spherical with a radius of 0.300 m. If the filled balloon is fastened to a vertical line, what is the tension in the line?

I don't even know what equation to use...! AHH
 
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HINT: It's a question about buoyancy.
 
is the tension equal to the force?
 
yes, but there are several forces involved here. ...
all dealing with one Volume.
 
Yes. The buoyant force is balanced by the tension in the string.
 
so would i use the equation B=density(fluid) x volume(fluid) x g?
 
Yes, substitute it in your \sum F_{y} = 0
 
so it would be Density(Helium) x what volume? x 9.81 ?
 
The forces acting on the balloon are gravity force, buoyant force and the tension in the line.

The buoyant force is applied by air of the atmosphere.

Buoyant force is equal to the weight of the displaced volume of the fluid.
 
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