Not Understanding This Simplification

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The discussion centers on the simplification of the differential equation x dy/dx + x^2y + y = 0 to the form dy/dx + (x + 1/x)y = 0. Participants clarify that dividing the original equation by x is crucial to achieve the correct form. There is confusion about the factorization of terms and the proper handling of y during the simplification process. Ultimately, the participants arrive at an understanding of the necessary steps to simplify the equation correctly. The conversation highlights the importance of careful manipulation of terms in differential equations.
snowJT
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I feel dumb because I can't see how you get from this:

x \frac{dy}{dx}+x^2y+y=0

to this

\frac{dy}{dx}+(x+\frac{1}{x})y=0

this is what I would of thought it would be...

\frac{dy}{dx}+(x+\frac{y}{x})+\frac{y}{x}=0

no?
 
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Why do you think it should be \frac{dy}{dx}+(x+\frac{y}{x})+\frac{y}{x}=0?

Divide the original equation by x; what do you get?
 
Factorize x^{2}y+y in the simplest manner.
What do you get?
 
cristo said:
Why do you think it should be \frac{dy}{dx}+(x+\frac{y}{x})+\frac{y}{x}=0?

Divide the original equation by x; what do you get?

you get \frac{dy}{dx}+(\frac{x^2}{x}+\frac{y}{x})+\frac{y}{x}=0

arildno said:
Factorize x^{2}y+y in the simplest manner.
What do you get?

you get \frac{x^2}{y}+1
 
No, you don't.

What does it mean to FACTORIZE?
 
y(x^2+1)

oh I see now... thanks

but why are you not dividing the y that's on the most right side of the LHS by x?
 
So, you have now your diff.eq in the form:
x\frac{dy}{dx}+(x^{2}+1)y=0
Multiply this equation with 1/x; what do you get?
 
sorry, I see it now... I'm just really bad at these things...
 
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