Nuclear Equation, not sure it its right

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The discussion focuses on writing a balanced nuclear equation for the bombardment of curium-246 with carbon-12, resulting in four neutrons and another nucleus. The initial attempt at the equation was incorrect due to a misunderstanding of mass and atomic number conservation. The correct nuclear equation is (246 96)Cm + (12 6)C => (254 98)No + 4(1 0)n, as the mass and atomic numbers must balance on both sides. The conversation also clarifies the notation for neutrons and protons, emphasizing the importance of accurate representation in nuclear equations. Ultimately, the correct solution reflects the conservation laws fundamental to nuclear reactions.
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Homework Statement



Write a balanced nuclear equation for the bombardment of curium-246, (246 96)Cm, with carbon-12 to produce four neutrons and another nucleus.

Homework Equations



conservation

The Attempt at a Solution



So this is what i got,
(246 96)Cm + (12 6)C => (246 102)No + 4(1 0)n
is this right?
 
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No. Thats not it. You have to conserve the mass number and the atomic number on both sides. For a neutron, its (1,1)n. So, sum up the mass numbers on the left side of the equation and the total mass of the know quantities on the right, and subtract them to get the mass of the atom produced.

Similarly, conserve the atomic number on both sides to get the atomic number of the nucleus produced to get your equation.
 
is it this? 1) (246 96)Cm + (12 6)C => (254 102)No + 4(1 0)n

or this?,

2) (246 96)Cm + (12 6)C => (254 98)No + 4(1 1)n

i don't have an example where the neutron is (1 1)n either, is it possible to have both a (1 0)n and (1 1)n neutron?

id think the first one, 1), looks like the right solution, but the textbook I am using has no solutions in it, so i have no idea if I am right or not.
 
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The second one is the right solution. Think about it. How can mass suddenly appear on the right side as it did in the first equation?

In fact, if you take actual masses (not just the whole numbers, but the decimals as well), you'll see that there is a mass defect, or mass difference between the two sides of the equation. This is converted into energy given quantitatively by Einstiens equation E=mc^2.

And youre right about the (1,0)n. I made a mistake. Sorry. A proton is (1,1)p.
 
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