Nullspace of A transpose x: A Geometric Interpretation

negation
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What does ATx=0 means?

Does this notation means if A = [3,2;1,2;4,4], then, AT = [3,1,4;2,2,4]

and ATx [x1;x2;x3] = 0?

The nullspace of the transposed of the matrix A?
 
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negation said:
What does ATx=0 means?
This doesn't mean anything to me. I believe it should be written ATx = 0. ATx is the product of A transpose and some vector x.
negation said:
Does this notation means if A = [3,2;1,2;4,4], then, AT = [3,1,4;2,2,4]

and ATx [x1;x2;x3] = 0?

The nullspace of the transposed of the matrix A?
 
Mark44 said:
This doesn't mean anything to me. I believe it should be written ATx = 0. ATx is the product of A transpose and some vector x.

What significance is there if a question ask if it is consistent or inconsistent?
ATx = 0
 
negation said:
What significance is there if a question ask if it is consistent or inconsistent?
ATx = 0
My guess is they're asking whether the multiplication is defined. If x ##\in## R3, and A is as you have in post 1, then Ax is not defined, but ATx is defined.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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