Number of emitted photons per second

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The discussion revolves around calculating the number of emitted photons per second from a 300mW LED with a 66% efficiency and an average wavelength of 500nm. Participants clarify that the energy of one photon is determined using the equation E=hf, where h is Planck's constant and f is the frequency derived from the wavelength. The total energy converted to light per second is calculated by multiplying the LED's power by its efficiency, yielding 198mJ. The final calculation for the number of photons emitted per second is confirmed to be approximately 5x10^17. The conversation emphasizes the importance of correctly applying the formulas and understanding the efficiency factor in the calculations.
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Homework Statement


The average wavelength that LED emits is 500nm. The electrical power of the LED is 300mW and the efficiency of turning energy into light is 66%. Number of emitted photons in unit time is?

Homework Equations


##E_f=hcf##
##\frac{Pt}{E_f}=number of photons##

The Attempt at a Solution


After calculating the energy of one photon i am to find the overall energy that is transformed into light. The energy is ##300x10^{-3}J## but how am i to include the efficiency? Just multiply the Energy with 0.66 and use that in the equation? The answer is suppose to yield ##5x10^{17} per second##
 
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Coldslooks said:

Homework Equations


##E_f=hcf##
First, this must make no sense. The correct one should be ##E=hf.##
Since you can get the energy of a photon, then given the amount of light you can calculate the number of the photons. Like what you said, the energy transferred to light per second is ##300mJ\cdot 66\%.##
 
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tommyxu3 said:
First, this must make no sense. The correct one should be ##E=hf.##
Since you can get the energy of a photon, then given the amount of light you can calculate the number of the photons. Like what you said, the energy transferred to light per second is ##300mJ\cdot 66\%.##
Yeah, your right, i haven't seen that I've put ##c## there, thanks.
Well then, ##\frac{E_t}{E_f}=\frac{198*10^{-3}J}{hf}##
##f=\frac{c}{w}=6*10^{14}## yes the rest is clear thanks :)
 
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