Number Theory (Finite and Infinite Sets)

Ankit Mishra
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Homework Statement



Why is R\Q not countably infinate or denumerable? Given R (Real Number) is not countably infinate or denumerable and Q (rational number) is denumerable.

Homework Equations



A set is said to be denumberable or countably infinate if there exists a bijestion of N (natural Number) onto S.

The Attempt at a Solution



Let Q be a subset of R and Let S be R-Q, which is denumerable. Via the defn there exists a bijection but R-Q is not bijective R-Q is the set of Real Numbers which is already not denumerable. I showed this to my prof and he said its not correct. He said to use Q u (R-Q)=R, we know Q is denumerable and R not to be denumerable use this to show R-Q is not denumerable? HOW!
 
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What you need to show is that the union of two countably infinite sets is countable. So take two sets {A_n} and {B_n}. Can you find a bijection from their union to the natural numbers? (hint: it's really easy)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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