Number Theory: Unclear Explanation of Divisibility Question

QIsReluctant
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Hello,

The following problem appears in my number theory text:

Show that if n=161038, then n divides 2n - 2.

The answer:

It is easy to verify that n = 2 * 73 * 1103 and n - 1 = 32 * 29 * 617. Hence 2n-1 - 1 is divisible by 29 - 1 = 7 * 73 and by 229 - 1, which in turn is divisible by 1103. This is done more or less by brute force: 210=-79 mod 1103, so 220=726 mod 1103, and 229= 1 mod 1103. So 2n - 2 is divisible by 2, 73, and 1103, and hence it is divisible by n.

I have tried to trace the reasoning in reverse. I understand how we get to the finish (by showing that the number is divisible by all of the relatively prime factors of n, but I don't understand how we actually show divisibility by those factors. Can someone show me the light? This chapter is on the theorems of Fermat, Wilson, and Euler.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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