- #1
stunner5000pt
- 1,443
- 4
Not a hard question really..
Using 3 - digit arithmetic calculcate 4/5 + 1/3 and compute the relative error
4/5 + 1/3 = 17/15
chopping 4/5 = 0.800 and 1/3 = 0.333
0.800 + 0.333 = 1.133 (chop) 1.13
im assuming that after this point there is no chopping
relative error aboslute value of \frac{\frac{17}{15} - 1.13}{\frac{17}{15}} = 0.0033
and the rleaitve error would be given in 3 siginificant digits?
sp 3.33 x 10^-3 is the relative error?
please tell me if i am right or wrong?
Your help is grealty appreciated!
Using 3 - digit arithmetic calculcate 4/5 + 1/3 and compute the relative error
4/5 + 1/3 = 17/15
chopping 4/5 = 0.800 and 1/3 = 0.333
0.800 + 0.333 = 1.133 (chop) 1.13
im assuming that after this point there is no chopping
relative error aboslute value of \frac{\frac{17}{15} - 1.13}{\frac{17}{15}} = 0.0033
and the rleaitve error would be given in 3 siginificant digits?
sp 3.33 x 10^-3 is the relative error?
please tell me if i am right or wrong?
Your help is grealty appreciated!
