A 1.5-cm tall object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. A converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens. What is the height and orientation with respect to the original object of the final image.(adsbygoogle = window.adsbygoogle || []).push({});

Okay, first, I find the distance of the image with respect to the diverging lens first.

-1/.2 = 1/di + 1/.5

di = -0.1428...

Then, I add that distance image to the converging lens distance to get the object distance for the converging lens.

0.08 + -.1428.. = .2228 m

Then I use the lens equation again except with that object distance and the focal length of the converging lens.

1/.17 = 1/di + 1/.2228

di = 1.395...

Then I take the magnification equation and use hi/h0 = -di/d0

hi / (1.5) = -(1.395)/(.5)

Solve for hi.. and get -4.185.

Apparently, that is not the answer. The answer key says that it is 1.4 cm with an inverted image. I don't really know how they get 1.4. Where did I go wrong in my work? Or am I wwwaaayy off with what I'm doing?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Object in front of two lenses

**Physics Forums | Science Articles, Homework Help, Discussion**