Object suspended by two cables, what are the tensions of each cable?

  • Thread starter Thread starter amyo16
  • Start date Start date
  • Tags Tags
    Cable Cables
AI Thread Summary
The discussion revolves around calculating the tensions in two cables supporting a 634 N weight, with one cable at a 46° angle and the other at 40°. The user attempted to solve the problem by breaking down the tension forces into their x and y components, aiming to balance these components. However, they received feedback indicating that their approach was mostly correct, except for a misunderstanding regarding the y components' equality. The user is encouraged to share their numerical results for further assistance. Accurate calculations are crucial for determining the correct tensions in the cables.
amyo16
Messages
1
Reaction score
0

Homework Statement


Consider there is a 634 N weight held by two cables that meet at a point above the weight. The left cable with tension T sub 2 makes an angle of 46° to the horizontal. The right cable with tension T sub 1 makes an angle of 40° to the horizontal.
a) What is the tension in the cable labeled T sub 1 slanted at an angle of 40°?
b) What is the tension in the cabel labeled T sub 2 slanted at an angle of 46°?


Homework Equations


I feel that the only relevant equation in this case is that the Tension always equals the Force. Therefore F sub T would equal the weight.


The Attempt at a Solution


I attempted to logically conclude that by splitting each tension force into components, the x components of each would have to equal 0 to balance each other out. I also thought that the y components of each would have to be equal to each other since they are the same height. So I had the equations Tsub1xsin40+Tsub2xsin46=634. I also had that Tsub1xcos40-Tsub2xcos46=0. Then I solved the second equation for Tsub1 and plugged it into the first equation and solved, but the answer was wrong. Help?
 
Physics news on Phys.org
Hi amyo16, wwelcome to PF.
Your method and equations are correct, (except the sentence
the y components of each would have to be equal to each other since they are the same height
which is not true). You might have miscalculated something, show your numerical results.

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top