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Odd and even functions, recangular coordinates

  1. Aug 5, 2009 #1
    1.if f and g are odd and even functions , respectively, such that f(a)= b and g(c) = b, b cannot equal 0,
    then [f(-a)/g(-c)] + f(-a) - g(-c) =

    A. -1
    B. -1-2b
    C. -1+2b
    D. 1-2b
    E. 1+2b

    2.if r= 4 sin(angle) is converted to rectangular coordinates , then
    A. x^2 + (y-2)^2 = 4
    B. (x-2)^2 + y^2 = 4
    C. x^2 +y^2 = 16
    D. x^2 +4y^2 = 4
    E (x-2)^2 + (y-2)^2 = 4


    i don't know how to solve number 1, i'm not sure my solution for number 2

    i don't get number 1
    number 2: i saw a problem like the question is r=4cos(angle) and solution is
    (x-2)^2 + y^2 = 2 , so i guessed A is solution for number 2, please help me.
  2. jcsd
  3. Aug 5, 2009 #2


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    You aren't going to get very far guessing at all the answers. For 1) look up the definition of odd and even and figure out what f(-a) and g(-c) might be in relation to b. For 2) multiply both sides by r and then look up some standard formulas for conversion between polar and rectangular. You have to show some effort here beyond just guessing.
  4. Aug 6, 2009 #3
    I agree that go back to the definition of odd and even function will be helpful.
    f(x)=-f(-x) and g(x)=g(-x),so f(-a)=-b, g(-c)=g(c)=b
    Now,I'm sure you know how to solve it
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